문제
MySQL
: 대소문자 구분하지 않아도 됨
내가 작성한 정답1 - like
select distinct city
from station
where city like '%a' or city like '%e' or city like '%i' or city like '%o' or city like '%u';
내가 작성한 정답2 - 정규표현식
select distinct city
from station
where city regexp '[aeiou]$'; // $: 문자열의 끝
내가 작성한 정답3 - substring, substr 둘 다 사용가능
select distinct city
from station
where substr(city,-1,1) in ('a','e','i','o','u');
select distinct city
from station
where substring(city,-1,1) in ('a','e','i','o','u');
내가 작성한 정답4 - right
select distinct city
from station
where right(city,1) in ('a','e','i','o','u');
Oracle
: 대소문자 구분 필요
내가 작성한 정답1 - like
: 도시의 첫글자는 대문자
select distinct city
from station
where city like '%a' or city like '%e' or city like '%i' or city like '%o' or city like '%u';
내가 작성한 정답2 - 정규표현식 regexp_like
select distinct city
from station
where regexp_like(city,'[aeiou]$');
내가 작성한 정답3 - substr
select distinct city
from station
where substr(city,-1,1) in ('a','e','i','o','u');
MS SQL Server - MySQL과 유사
: 대소문자 구분 x
내가 작성한 정답1 - like
select distinct city
from station
where city like '%a' or city like '%e' or city like '%i' or city like '%o' or city like '%u';
내가 작성한 정답2 - like2
select distinct city
from station
where city like '%[aeiou]';
substring은 사용 불가 → 음수 지원 안됨
내가 작성한 정답3 - right
select distinct city
from station
where right(city,1) in ('a','e','i','o','u');
DB2 - Oracle과 유사
내가 작성한 정답1 - like
select distinct city
from station
where city like '%a' or city like '%e' or city like '%i' or city like '%o' or city like '%u';
substr - 음수지원 안됨
정리!
DBMS | 문자추출 | left 유무 | 정규표현식 |
MS SQL Server | substring | o | x → like로 표현가능 |
MySQL | substring | o | o → regexp |
Oracle | substr | x | o → regexp_like(colunm,정규식) |
DB2 | substr | x | x → substr로 표현가능 |
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