문제
MYSQL
내가 작성한 정답
WITH A AS (
SELECT CAR_ID,
CASE
WHEN START_DATE <= '2022-10-16' AND END_DATE >= '2022-10-16' THEN '대여중'
ELSE '대여 가능'
END AS AVAILABILITY
FROM CAR_RENTAL_COMPANY_RENTAL_HISTORY
)
SELECT CAR_ID, MAX(AVAILABILITY)
FROM A
GROUP BY CAR_ID
ORDER BY CAR_ID DESC
다른 사람들이 작성한 정답
SELECT CAR_ID
, CASE
WHEN MAX('2022-10-16' BETWEEN START_DATE AND END_DATE) = 1 THEN '대여중'
ELSE '대여 가능'
END AS AVAILABILITY
FROM CAR_RENTAL_COMPANY_RENTAL_HISTORY
GROUP BY CAR_ID
ORDER BY CAR_ID DESC
집계함수 MAX()안에 연산자를 넣으면 연산이 참이라면 1을 출력하고 거짓이라면 0을 출력
ORACLE
내가 작성한 정답
WITH A AS (
SELECT CAR_ID,
CASE
WHEN TO_CHAR(START_DATE,'YYMMDD') <= '221016' AND TO_CHAR(END_DATE,'YYMMDD') >= '221016' THEN '대여중'
ELSE '대여 가능'
END AS AVAILABILITY
FROM CAR_RENTAL_COMPANY_RENTAL_HISTORY
)
SELECT CAR_ID, MAX(AVAILABILITY)
FROM A
GROUP BY CAR_ID
ORDER BY CAR_ID DESC
글자에서도 max와 min 비교 가능하다!
order by asc순으로 min → max (desc)로 생각하면 간단하다.
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